Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Cumulative Review: 29



Work Step by Step

We are given that $5x-3\leq10$ or $x+1\geq5$. Therefore, a solution only needs to satisfy one of the inequalities. We can first solve $5x-3\leq10$ for x. Add 3 to both sides. $5x\leq13$ Divide both sides by 5. $x\leq\frac{13}{5}$ Next, can first solve $x+1\geq5$ for x. Subtract 1 from both sides. $x\geq4$ Therefore, the solution set consists of all real numbers that are less than or equal to $\frac{13}{5}$ or greater than or equal to 4.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.