Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Cumulative Review - Page 199: 9f

Answer

$\frac{2}{3}\lt\frac{3}{4}$

Work Step by Step

$\frac{2}{3}=\frac{2}{3}\times\frac{4}{4}=\frac{8}{12}$ $\frac{3}{4}=\frac{3}{4}\times\frac{3}{3}=\frac{9}{12}$ $\frac{8}{12}$ is to the left of $\frac{9}{12}$ on the number line. Therefore, $\frac{2}{3}$ is less than $\frac{3}{4}$ in value.
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