Answer
69, 71, and 73
Work Step by Step
An odd integer has a value of exactly 2 less than its next consecutive odd integer. And each following consecutive odd integer will be exactly 2 more in value than the previous odd integer.
The sum of 3 consecutive odd integers:
$x+(x+2)+(x+2+2)=(x+x+x)+(2+2+2)=3x+6$
We can set this sum equal to 213.
$3x+6=213$
Subtract 6 from both sides.
$3x=207$
Divide both sides by 3.
$x=69$
Number 1: 69
Number 2: 69+2=71
Number 3: 69+2+2=73
