Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Cumulative Review: 38



Work Step by Step

We are given that $|x+3|\gt1$. Therefore, $x+3\gt1$ or $x+3\lt-1$. We can solve both of these inequalities to find solutions. For $x+3\gt1$, subtract 3 from both sides. $x\gt-2$ For $x+3\lt-1$, subtract 3 from both sides. $x\lt-4$ Therefore, the solution set consists of all values of x that are less than -4 or greater than -2.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.