## Intermediate Algebra (6th Edition)

$[\frac{-1}{2},\frac{3}{2})$
$\frac{-1}{2} \leq \frac{4x-1}{6} \lt \frac{5}{6}$ Using the inequality properties, multiply all parts by the LCD 6. $6(\frac{-1}{2}) \leq 6(\frac{4x-1}{6}) \lt 6(\frac{5}{6})$ $-3 \leq 4x-1 \lt 5$ Add 1 to all parts. $-3+1 \leq 4x-1+1 \lt 5+1$ $-2 \leq 4x \lt 6$ Divide by 4 to get $x$. $\frac{-2}{4} \leq \frac{4x}{4} \lt \frac{6}{4}$ $\frac{-1}{2} \leq x \lt \frac{3}{2}$ In Interval Notation:$[\frac{-1}{2},\frac{3}{2})$