## Intermediate Algebra (6th Edition)

$(0,\frac{14}{3}]$
$-6 \lt 3(x-2) \leq 8$ Using the properties of inequalities, divide all parts by 3 $\frac{-6}{3} \lt \frac{3(x-2)}{3} \leq \frac{8}{3}$ $-2 \lt x-2 \leq \frac{8}{3}$ Add 2 to all parts, $-2+2 \lt x-2 +2 \leq \frac{8}{3}+2$ $0 \lt x \leq \frac{8}{3}+2$ Take LCD $0 \lt x \leq \frac{8+6}{3}$ $0 \lt x \leq \frac{14}{3}$ In Interval Notation: $(0,\frac{14}{3}]$