## Intermediate Algebra (6th Edition)

The solution is $(-3,0]$
$5x\le0$ and $-x+5\lt8$ Solve the first inequality: $5x\le0$ Take $5$ to divide the right side: $x\le\dfrac{0}{5}$ $x\le0$ Expressing in interval notation: $(-\infty,0]$ Solve the second inequality: $-x+5\lt8$ Take $5$ to the right side: $-x\lt8-5$ $-x\lt3$ Change the sign on both sides and reverse the direction of the inequality sign: $x\gt-3$ Expressing in interval notation: $(-3,\infty)$ Since the compound inequality is formed by the word "and", the solution is composed by the numbers that satisfy both inequalities at the same time: The solution is $(-\infty,0]\cap(-3,\infty)$ or $(-3,0]$