## Intermediate Algebra (6th Edition)

Solving the inequalities separately, then \begin{array}{l}\require{cancel} x+3\ge3 \\\\ x\ge3-3 \\\\ x\ge0 ,\\\\\text{AND}\\\\ x+3\le2 \\\\ x\le2-3 \\\\ x\le-1 .\end{array} There are no common values between $x\ge0$ and $x\le-1$. Hence, there is no solution.