Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.5 - The Binomial Theorem - Exercise Set - Page 664: 40

Answer

$525m^5n^2$

Work Step by Step

Using the $(r+1)$st term of the expansion of $(a+b)^n$, which is given by $\dfrac{n!}{(n-r)!r!}a^{n-r}b^r$, then the $ 3 $rd term of $ (m+5n)^7 $ is \begin{array}{l} \dfrac{7!}{5!2!}(m)^{5}(5n)^{2} \\\\= 21m^5(25n^2) \\\\= 525m^5n^2 \end{array}
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