Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.5 - The Binomial Theorem - Exercise Set - Page 664: 30

Answer

$81+216a+216a^2+96a^3+16a^4$

Work Step by Step

Using the Binomial Formula, the expression $ (3+2a)^4 $ expands to \begin{array}{l} 3^4(2a)0+ \dfrac{4}{1!}3^3(2a)1+ \dfrac{4\cdot3}{2!}3^2(2a)2+ \dfrac{4\cdot3\cdot2}{3!}3^1(2a)3+ \dfrac{4\cdot3\cdot2\cdot1}{4!}3^0(2a)4 \\\\= 81+216a+216a^2+96a^3+16a^4 \end{array}
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