Answer
$6x^4y^2$
Work Step by Step
Using the $(r+1)$st term of the expansion of $(a+b)^n$, which is given by $\dfrac{n!}{(n-r)!r!}a^{n-r}b^r$, then the $
3
$rd term of $
(x+y)4
$ is
\begin{array}{l}
\dfrac{4!}{2!2!}(x)^{4}(y)^{2}
\\\\=
6x^4y^2
\end{array}
