Chapter 11 - Section 11.5 - The Binomial Theorem - Exercise Set - Page 664: 33

$d^7$

Using the $(r+1)$st term of the expansion of $(a+b)^n$, which is given by $\dfrac{n!}{r!(n-r)!}a^{n-r}b^r$, then the $ 8 $th term of $ (2c+d)^7 $ is \begin{array}{l} \dfrac{7!}{7!0!}(2c)^{0}(d)^{7} \\\\= d^7 \end{array}