Answer
The first term = 660,000
The second term = 1,320,000
The third term = 2,640,000
The fourth term = 5,280,000
The fifth term = 10,560,000
For 2010, the number of infested acres = 10,560,000
Work Step by Step
For the geometric sequence,
the first term, $a_{1}$ = 660,000;
the second term, $a_{2} = 660000(r)^{n-1}$ where r = 2 and n =2,
$a_{2} = 660000(2)^{2-1} = 1,320,000$;
the third term, $a_{3} = 660000(r)^{n-1}$ where r = 2 and n =3,
$a_{3} = 660000(2)^{3-1} = 2,640,000$;
the fourth term, $a_{4} = 660000(r)^{n-1}$ where r = 2 and n =4,
$a_{4} = 660000(2)^{4-1} = 5,280,000$;
the fifth term, $a_{5} = 660000(r)^{n-1}$ where r = 2 and n =5,
$a_{5} = 660000(2)^{5-1} = 10,560,000$;
For 2010, it is five years from 2006, so, n = 5,
the number of infested acres is $a_{5} = 10,560,000$
