Answer
$a_{11}=\dfrac{19}{2}$
Work Step by Step
Using $a_n=a_1+(n-1)d$ then,
\begin{array}{l}
a_{11}=2+(11-1)\left(\dfrac{3}{4}\right)\\
a_{11}=2+(10)\left(\dfrac{3}{4}\right)\\
a_{11}=2+\dfrac{15}{2}\\
a_{11}=\dfrac{19}{2}
.\end{array}
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