Answer
$a_6=\dfrac{243}{8}$
Work Step by Step
Using $a_n=a_1r^{n-1}$ then,
\begin{array}{l}
a_6=4\left( \dfrac{3}{2} \right)^{6-1}\\\\
a_6=4\left( \dfrac{243}{32} \right)\\\\
a_6=\dfrac{243}{8}
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 11 - Review - Page 667: 16
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