Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Review - Page 667: 19

Answer

$a_n=\dfrac{3}{10}\left(\dfrac{1}{10} \right)^n$

Work Step by Step

The sequence $ \dfrac{3}{10},\dfrac{3}{100},\dfrac{3}{1000},... $ forms a geometric sequence. Hence, the general term of the sequence is \begin{array}{l} a_n=\dfrac{3}{10}\left(\dfrac{1}{10} \right)^n .\end{array}
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