Answer
$a_{n}= 42+8n$
Work Step by Step
Given sequence is $50,58,66....$
First term, $a_{1}= 50$
Common difference, $d = 58-50 = 8$
$a_{n}$ of the arithmetic sequence is $a_{n} = a_{1} + (n-1)d$
Substituting $a_{1}$ and $d$
$a_{n}= 50+(n-1)8$
$a_{n}=50+8n-8$
$a_{n}= 42+8n$
