Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Section R.3 - Exponents, Roots, and Order of Operations - R.3 Exercises: 78



Work Step by Step

Using order of operations, the given expression, $ \dfrac{-4\left(\dfrac{12-(-8)}{3\cdot2+4}\right)-5(-1-7)}{-9-(-7)-[5-(-8)]} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{-4\left(\dfrac{12+8}{6+4}\right)-5(-8)}{-9+7-[5+8]} \\\\= \dfrac{-4\left(\dfrac{20}{10}\right)+40}{-2-13} \\\\= \dfrac{-4\left(2\right)+40}{-15} \\\\= \dfrac{-8+40}{-15} \\\\= \dfrac{32}{-15} \\\\= -\dfrac{32}{15} .\end{array}
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