Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Section R.3 - Exponents, Roots, and Order of Operations - R.3 Exercises: 76

Answer

$\text{undefined}$

Work Step by Step

Using order of operations, the given expression, $ \dfrac{3(-4)+(-5)(-8)}{2^3-2-6} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{-12+40}{8-2-6} \\\\= \dfrac{28}{6-6} \\\\= \dfrac{28}{0} \\\\= \text{undefined} .\end{array}
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