Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Section R.3 - Exponents, Roots, and Order of Operations - R.3 Exercises: 77

Answer

$-7$

Work Step by Step

Using order of operations, the given expression, $ \dfrac{5-3\left(\dfrac{-5-9}{-7}\right)-6}{-9-11+3\cdot7} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{5-3\left(\dfrac{-14}{-7}\right)-6}{-9-11+21} \\\\= \dfrac{5-3\left(2\right)-6}{-20+21} \\\\= \dfrac{5-6-6}{1} \\\\= \dfrac{-1-6}{1} \\\\= \dfrac{-7}{1} \\\\= -7 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.