Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Section R.3 - Exponents, Roots, and Order of Operations - R.3 Exercises: 71

Answer

$2$

Work Step by Step

Using order of operations, the given expression, $ -14\left(-\dfrac{2}{7}\right)\div(2\cdot6-10) ,$ simplifies to \begin{array}{l}\require{cancel} -\cancel{14}^2\left(-\dfrac{2}{\cancel{7}}\right)\div(12-10) \\\\= 4\div2 \\\\= 2 .\end{array}
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