Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Section R.3 - Exponents, Roots, and Order of Operations - R.3 Exercises: 71



Work Step by Step

Using order of operations, the given expression, $ -14\left(-\dfrac{2}{7}\right)\div(2\cdot6-10) ,$ simplifies to \begin{array}{l}\require{cancel} -\cancel{14}^2\left(-\dfrac{2}{\cancel{7}}\right)\div(12-10) \\\\= 4\div2 \\\\= 2 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.