Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Section R.3 - Exponents, Roots, and Order of Operations - R.3 Exercises - Page 30: 63



Work Step by Step

Using order of operations, the given expression, $ -7(\sqrt{36})-(-2)(-3) ,$ simplifies to \begin{array}{l}\require{cancel} -7(\sqrt{(6)^2})-(6) \\\\= -7\cdot6-6 \\\\= -42-6 \\\\= -48 .\end{array}
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