Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 9 - Review Exercises - Page 638: 51

Answer

$\left\{\dfrac{1}{9}\right\}$

Work Step by Step

Since $\log_b y=x$ implies $y=b^x$, the given equation, $ \log_3(9x+8)=2 $, implies \begin{align*}\require{cancel} 9x+8&=3^2 \\ 9x+8&=9 .\end{align*} Using the properties of equality, the equation above is equivalent to \begin{align*}\require{cancel} 9x+8-8&=9-8 \\ 9x&=1 \\\\ \dfrac{\cancel9x}{\cancel9}&=\dfrac{1}{9} \\\\ x&=\dfrac{1}{9} .\end{align*} Hence, the solution set of the equation $ \log_3(9x+8)=2 $ is $ \left\{\dfrac{1}{9}\right\} $.
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