Answer
$0.9251$
Work Step by Step
Using the Change-of-Base Formula, the given expression, $
\log_{16}13
,$ is equivalent to
\begin{align*}\require{cancel}
&
\dfrac{\log_{10}13}{\log_{10}16}
\\\\&=
\dfrac{\log 13}{\log 16}
\\\\&\approx
0.9251
.\end{align*}
Hence, the expression $
\log_{16}13
$ is approximately equal to $
0.9251
$.
