Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 8 - Chapter R-8 - Cumulative Review Exercises - Page 578: 3

Answer

$\left\{\dfrac{11}{10},\dfrac{7}{2}\right\}$

Work Step by Step

The given equation, $ |6x-9|=|-4x+2| $ is equivalent to \begin{align*} 6x-9&=-4x+2 \\\text{ OR }\\ 6x-9&=-(-4x+2) .\end{align*} Solving these equations separately results to \begin{array}{l|r} 6x-9=-4x+2 & 6x-9=-(-4x+2) \\ 6x+4x=2+9 & 6x-9=4x-2 \\ 10x=11 & 6x-4x=-2+9 \\\\ x=\dfrac{11}{10} & 2x=7 \\\\ & x=\dfrac{7}{2} .\end{array} Hence, the solution set of the equation $ |6x-9|=|-4x+2| $ is $\left\{\dfrac{11}{10},\dfrac{7}{2}\right\}$.
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