Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 8 - Chapter R-8 - Cumulative Review Exercises - Page 578: 12

Answer

A function $f(x)=\dfrac{4x}{5}-3$ Domain: $(-\infty,\infty)$ Range: $(-\infty,\infty)$ Graph of $4x-5y=15$

Work Step by Step

The given equation, $ 4x-5y=15 $, is a line. To graph this equation, use substitution to find two points that are on the line defined by the equation. Using substitution, \begin{array}{l|r} \text{If }x=0: & \text{If }x=5: \\\\ 4(0)-5y=15 & 4(5)-5y=15 \\ 0-5y=15 & 20-5y=15 \\ -5y=15 & -5y=15-20 \\\\ y=\dfrac{15}{-5} & -5y=-5 \\\\ y=-3 & y=\dfrac{-5}{-5} \\\\ & y=1 .\end{array} Therefore, the points $(0,-3)$ and $(5,1)$ are on the line defined by the given equation. Plotting these points and connecting these give the graph of $4x-5y=15$ (see graph above). Based on the graph above, the equation is a function since it will pass the Vertical Line Test. That is, a vertical line drawn anywhere will intersect the graph above in at most $1$ point. Hence, the function notation of the given equation is $ f(x)=\dfrac{4x}{5}-3 $. Using the graph, the domain (values of $x$ used in the graph) is the set of all real numbers. The range (values of $y$ used in the graph) is the set of all real numbers.
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