Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 6 - Section 6.2 - Adding and Subtracting Rational Expressions - 6.2 Exercises: 25

Answer

$z(z-2)$

Work Step by Step

We are given the denominators $z-2$ and $z$. In order to find the least common denominator, we must factor each denominator. $z-2$ cannot be simplified further $z$ cannot be simplified further Next, we multiply together all distinct factors from each denominator, with each factor raised to the greatest power that occurs in any denominator. $LCD=z\times(z-2)=z(z-2)$
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