Answer
$-\frac{2}{x^{3}}$
Work Step by Step
$\frac{9}{4x^{3}}-\frac{17}{4x^{3}}=\frac{9-17}{4x^{3}}=\frac{-8}{4x^{3}}=\frac{-8\div4}{4x^{3}\div4}=-\frac{2}{x^{3}}$
Intermediate Algebra (12th Edition)
by Lial, Margaret L.; Hornsby, John; McGinnis, Terry
Published by
Pearson
ISBN 10:
0321969359
ISBN 13:
978-0-32196-935-4
Chapter 6 - Section 6.2 - Adding and Subtracting Rational Expressions - 6.2 Exercises - Page 382: 13
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