#### Answer

$\frac{5}{p+3}$

#### Work Step by Step

$\frac{-3p+7}{p^{2}+7p+12}+\frac{8p+13}{p^{2}+7p+12}=\frac{-3p+7+8p+13}{p^{2}+7p+12}=\frac{5p+20}{p^{2}+7p+12}=\frac{5(p+4)}{(p+3)(p+4)}=\frac{5}{p+3}\times\frac{p+4}{p+4}=\frac{5}{p+3}\times1=\frac{5}{p+3}$