#### Answer

$\frac{2}{x-4}$

#### Work Step by Step

$\frac{5x+6}{x^{2}+x-20}+\frac{4-3x}{x^{2}+x-20}=\frac{5x+6+4-3x}{x^{2}+x-20}=\frac{2x+10}{x^{2}+x-20}=\frac{2(x+5)}{(x-4)(x+5)}=\frac{2}{x-4}\times\frac{x+5}{x+5}=\frac{2}{x-4}\times1=\frac{2}{x-4}$

Published by
Pearson

ISBN 10:
0321969359

ISBN 13:
978-0-32196-935-4

$\frac{2}{x-4}$

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