Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 6 - Section 6.2 - Adding and Subtracting Rational Expressions - 6.2 Exercises - Page 382: 20

Answer

$\frac{2}{x-4}$

Work Step by Step

$\frac{5x+6}{x^{2}+x-20}+\frac{4-3x}{x^{2}+x-20}=\frac{5x+6+4-3x}{x^{2}+x-20}=\frac{2x+10}{x^{2}+x-20}=\frac{2(x+5)}{(x-4)(x+5)}=\frac{2}{x-4}\times\frac{x+5}{x+5}=\frac{2}{x-4}\times1=\frac{2}{x-4}$
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