Answer
2
Work Step by Step
$\frac{6y+12}{4y+3}+\frac{2y-6}{4y+3}=\frac{6y+12+2y-6}{4y+3}=\frac{(6y+2y)+(12-6)}{4y+3}=\frac{(8y)+(6)}{4y+3}=\frac{8y+6}{4y+3}=\frac{2}{1}=2$
Intermediate Algebra (12th Edition)
by Lial, Margaret L.; Hornsby, John; McGinnis, Terry
Published by
Pearson
ISBN 10:
0321969359
ISBN 13:
978-0-32196-935-4
Chapter 6 - Section 6.2 - Adding and Subtracting Rational Expressions - 6.2 Exercises - Page 382: 16
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