Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Review Exercises: 20



Work Step by Step

$\frac{6m^{-4}n^{3}}{-3mn^{2}}=\frac{6}{-3}\times\frac{m^{-4}}{m}\times\frac{n^{3}}{n^{2}}=-2\times m^{-4-1}\times n^{3-2}=-2\times m^{-5}\times n=-2m^{-5}n=-\frac{2n}{m^{5}}$
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