Answer
$-\frac{2n}{m^{5}}$
Work Step by Step
$\frac{6m^{-4}n^{3}}{-3mn^{2}}=\frac{6}{-3}\times\frac{m^{-4}}{m}\times\frac{n^{3}}{n^{2}}=-2\times m^{-4-1}\times n^{3-2}=-2\times m^{-5}\times n=-2m^{-5}n=-\frac{2n}{m^{5}}$
Intermediate Algebra (12th Edition)
by Lial, Margaret L.; Hornsby, John; McGinnis, Terry
Published by
Pearson
ISBN 10:
0321969359
ISBN 13:
978-0-32196-935-4
Chapter 4 - Review Exercises - Page 316: 20
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