Answer
$\frac{1}{z^{15}}$
Work Step by Step
$(z^{-3})^{3}z^{-6}=z^{-3\times3}z^{-6}=z^{-9}z^{-6}=z^{-9+(-6)}=z^{-9-6}=z^{-15}=\frac{1}{z^{15}}$
Intermediate Algebra (12th Edition)
by Lial, Margaret L.; Hornsby, John; McGinnis, Terry
Published by
Pearson
ISBN 10:
0321969359
ISBN 13:
978-0-32196-935-4
Chapter 4 - Review Exercises - Page 316: 13
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