Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Review Exercises: 12

Answer

$\frac{y^{6}}{x^{2}}$

Work Step by Step

$(xy^{-3})^{-2}=x^{-2}\times (y^{-3})^{-2}=x^{-2}\times y^{-3\times-2}=x^{-2}\times y^{6}=\frac{1}{x^{2}}\times y^{6}=\frac{y^{6}}{x^{2}}$
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