Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Review Exercises - Page 316: 16



Work Step by Step

Using the laws of exponents, the given expression, $ \left( \dfrac{5z^{-3}}{z^{-1}} \right)\dfrac{5}{z^2} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{5z^{-3}\cdot5}{z^{-1}\cdot z^2} \\\\= \dfrac{5^{1+1}z^{-3}}{z^{-1+2}} \\\\= \dfrac{5^{2}z^{-3}}{z^{1}} \\\\= 5^{2}z^{-3-1} \\\\= 25z^{-4} \\\\= \dfrac{25}{z^4} .\end{array}
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