Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Review Exercises - Page 316: 2

Answer

$\frac{1}{81}$

Work Step by Step

$(\frac{1}{3})^{4}=\frac{1}{3}\times\frac{1}{3}\times\frac{1}{3}\times\frac{1}{3}=\frac{1\times1\times1\times1}{3\times3\times3\times3}=\frac{1}{81}$
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