Answer
$(-3,-2,-3)$
Work Step by Step
In this case the transformation is linear if $T(v_1+v_2)=T(v_1)+T(v_2)$ and $T(av_1)=aT(v_1)$ for any $v_1,v_2$ in the domain and any $a$ scalar.
Hence $T(-2,1,0)=2T(1,1,1)+T(0,-1,2)-4T(1,0,1)=2(2,0,-1)+(-3,2,-1)-4(1,1,0)=(4,0,-2)+(-3,2,-1)+(-4,-4,0)=(-3,-2,-3)$