Answer
$(11,-8)$
Work Step by Step
We know that $T(v_1,v_2)=(v_1+v_2,v_1-v_2)$
Thus $T(3,-4)=(3+(-4),3-(-4))=(-1,7)$
Let $(x,y)$ be the pre-image of $(3,19)$. Then $T(x,y)=(x+y,x-y)=(3,19).$
Thus $x+y=3,x-y=19$ From this we get $x=11,y=-8$.
So the pre-image of $(3,19)$ is $(11,-8)$