Elementary Linear Algebra 7th Edition

Published by Cengage Learning
ISBN 10: 1-13311-087-8
ISBN 13: 978-1-13311-087-3

Chapter 5 - Inner Product Spaces - Review Exercises - Page 284: 15

Answer

$$\cos \theta=0 $$ that is, $\theta=\frac{\pi}{2}$.

Work Step by Step

Let $u=(2,2),\quad v=(-3,3), \quad =u\cdot v $. The angle $\theta$ between $u$ and $v$ is given by the formula $$\cos \theta=\frac{\langle u, v\rangle}{\|u\| \cdot\|v\|}=\frac{-6+6}{\sqrt{ 4+4}\sqrt{ 9+9}}=0 $$ that is, $\theta=\frac{\pi}{2}$.
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