Answer
$$c=-\pm1.$$
Work Step by Step
$$\| c(2,2,-1)\|=3\Longrightarrow |\|c (2,2,-1)\|^2=9 \Longrightarrow c^2 (4+4+1)=9$$
then, we get $c^2=1$ and hence
$$c=-\pm1.$$
Elementary Linear Algebra 7th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
1-13311-087-8
ISBN 13:
978-1-13311-087-3
Chapter 5 - Inner Product Spaces - Review Exercises - Page 284: 14
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