## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Substituting the $x$ and $y$-coordinates of $( 1,3 )$ in the given equation, $y=2x-5 ,$ results to \begin{array}{l}\require{cancel} y=2x-5 \\\\ 3=2(1)-5 \\\\ 3=2-5 \\\\ 3=-3 \text{ (FALSE)} .\end{array} Since the substitution above resulted in a FALSE statement, then the given point is $\text{ NOT a solution }$ to the given equation.