Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter R - Elementary Algebra Review - R.3 Introduction to Graphing - R.3 Exercise Set - Page 954: 10


a solution

Work Step by Step

Substituting the $x$ and $y$-coordinates of $( -1,4 )$ in the given equation, $ 4x+3y=8 ,$ results to \begin{array}{l}\require{cancel} 4x+3y=8 \\\\ 4(-1)+3(4)=8 \\\\ -4+12=8 \\\\ 8=8 \text{ (TRUE)} .\end{array} Since the substitution above resulted in a TRUE statement, then the given point is $\text{ a solution }$ to the given equation.
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