# Chapter R - Elementary Algebra Review - R.3 Introduction to Graphing - R.3 Exercise Set - Page 954: 30

$\text{$x$-intercept: } 1 \\\text{$y$-intercept: } -\dfrac{1}{2}$

#### Work Step by Step

Substituting $y=0,$ then \begin{array}{l}\require{cancel} 2y+1=x \\\\ 2(0)+1=x \\\\ 0+1=x \\\\ 1=x .\end{array} Hence, the $x$-intercept is $1 .$ Substituting $x=0,$ then \begin{array}{l}\require{cancel} 2y+1=x \\\\ 2y+1=0 \\\\ 2y=-1 \\\\ y=-\dfrac{1}{2} .\end{array} Hence, the $y$-intercept is $-1/2 .$ The given equation has the following characteristics: \begin{array}{l}\require{cancel} \text{$x$-intercept: } 1 \\\text{$y$-intercept: } -\dfrac{1}{2} .\end{array} Using the intercepts, the graph is shown above.

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