Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter R - Elementary Algebra Review - R.3 Introduction to Graphing - R.3 Exercise Set: 43

Answer

perpendicular

Work Step by Step

Using $y=mx+b$ where $m$ is the slope, the slope of the first equation, \begin{array}{l}\require{cancel} x+y=5 \\\\ y=-x+5 \end{array} is $m_1= -1 .$ Using $y=mx+b$ where $m$ is the slope, the slope of the second equation, \begin{array}{l}\require{cancel} x-y=1 \\\\ -y=-x+1 \\\\ y=x-1 \end{array} is $m_2= 1 .$ Since $m_1\cdot m_2=-1,$ then the given lines are $\text{ perpendicular .}$
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