## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$\text{Slope: } \dfrac{1}{2} \\\text{$y$-intercept: } -\dfrac{3}{2}$
The given equation is equivalent to \begin{array}{l}\require{cancel} x-2y=3 \\\\ -2y=-x+3 \\\\ \dfrac{-2y}{-2}=\dfrac{-1}{-2}x+\dfrac{3}{-2} \\\\ y=\dfrac{1}{2}x-\dfrac{3}{2} .\end{array} Using $y=mx+b$ (where $m$ is the slope and $b$ is the $y$-intercept) or the Slope-Intercept Form of linear equations, then the equation, $y=\dfrac{1}{2}x-\dfrac{3}{2} ,$ has the following properties: \begin{array}{l}\require{cancel} \text{Slope: } \dfrac{1}{2} \\\text{$y$-intercept: } -\dfrac{3}{2} .\end{array}