Chapter 5 - Polynomials and Factoring - 5.7 Solving Quadratic Equations by Factoring - 5.7 Exercise Set - Page 353: 86

$$x=-4,\:x=-3,\:x=3$$

In order to solve this equation, we simplify until the variable is isolated on one side of the equation. Doing this, we find: $$ x^3+4x^2-9x-36=0\\ \left(x+4\right)\left(x+3\right)\left(x-3\right)=0 \\ x=-4,\:x=-3,\:x=3$$