Chapter 5 - Polynomials and Factoring - 5.7 Solving Quadratic Equations by Factoring - 5.7 Exercise Set - Page 353: 76

$$x=-\frac{1}{4},\:x=-\frac{1}{5},\:x=\frac{2}{3}$$

To solve the equation, we first factor the equation. Next, we set each of the factors equal to zero. Doing this, we find: $$\left(4x+1\right)\left(5x+1\right)\left(3x-2\right) \\ x=-\frac{1}{4},\:x=-\frac{1}{5},\:x=\frac{2}{3}$$