Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.7 Solving Quadratic Equations by Factoring - 5.7 Exercise Set - Page 353: 80

Answer

$$t=5,\:t=3$$

Work Step by Step

In order to solve the equation, we first simplify both sides of the equation. Next, we isolate the variable. Doing this, we find: $$ t^2-10t+25=10-2t \\ t^2-8t+15=0 \\ (t-5)(t-3)=0\\ t=5,\:t=3$$
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