Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.7 Solving Quadratic Equations by Factoring - 5.7 Exercise Set - Page 353: 84

Answer

$$x=\frac{5}{9},\:x=-\frac{5}{9}$$

Work Step by Step

In order to solve this equation, we simplify until the variable is isolated on one side of the equation. Doing this, we find: $$ \frac{27}{25}x^2=\frac{1}{3} \\ x^2=\frac{25}{81}\\ x=\frac{5}{9},\:x=-\frac{5}{9}$$
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