Chapter 5 - Polynomials and Factoring - 5.7 Solving Quadratic Equations by Factoring - 5.7 Exercise Set - Page 353: 85

$$x=2,\:x=-1,\:x=1$$

In order to solve this equation, we simplify until the variable is isolated on one side of the equation. Doing this, we find: $$ x^3-2x^2-x+2=0 \\ \left(x-2\right)\left(x+1\right)\left(x-1\right)=0\\ x=2,\:x=-1,\:x=1$$